20x^2=120

Solution for 20x^2=120 equation:

20x^2=120

We move all terms to the left:

20x^2-(120)=0

a = 20; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·20·(-120)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{6}}{2*20}=\frac{0-40\sqrt{6}}{40}
=-\frac{40\sqrt{6}}{40}
=-\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{6}}{2*20}=\frac{0+40\sqrt{6}}{40}
=\frac{40\sqrt{6}}{40}
=\sqrt{6}
$